matlab - servo motor transfer function matlab code

matlab - servo motor transfer function matlab code

Servo Motor transfer function Using in MATLAB software

Servo Motor

Servo Motor, we can say Control motors and used in feedback control systems  (close loop) as output actuators. Its newer apply for continue energy transfer or conversion. The standard of the Servo motor is like that of the other electromagnetic motor, yet the development and the activity are extraordinary. 

Their capacity rating differs from a small amount of a watt to a couple hundred watts.

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The servo motor is most usually utilized for high innovation gadgets in the industrial applications like robotics technology. 

It is an independent electrical gadget that turns portions of machine with high proficiency and incredible exactness. 

Additionally the yield shaft of this motor can be moved to a specific angle. Additionally the yield shaft of this engine can be moved to a specific point.

The rotor inertia of the motors is low and have a high speed of reaction. The rotor of the Motor has the extensive length and lesser diameter. They work at low speed and now and then even at the zero speed. 

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The servo motor is generally utilized in home electronics gadgets, toys, cars, airplanes, radar and computers PCs, robot, machine tool, tracking and guidance systems, processing controlling, and so on.

The Applications of the Servomotor

• Radar system and process controller.
• Computers and robotics.
• Machine tools.
• Tracking and guidance systems.
• Robotics
• Conveyor belts
• Camera auto focus
• Solar tracking system

Type of Servo Motor

Ø DC Servo Motor

Ø AC servomotor

o   Two Phase AC Servo Motor

o   Three Phase AC Servo Motor

DC Servo Motor

Matlab Code- 

clc

clear all

close all

 

J=0.01;

f=0.1;

K=0.01;

R=1;

L=0.5;

s=tf('s');

P_motor=K/(s*((J*s+f)*(L*s+R)+K^2))

bode(P_motor)

grid

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Result- 

P_motor =

 

               0.01

  -------------------------------

  0.005 s^3 + 0.06 s^2 + 0.1001 s

 

Continuous-time transfer function.

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AC Servo Motor

Matlab Code- 

clc

clear all

close all

 

% Transfer function, Gm (s) = Km / (1+ s *Tm)

 

%% Find out Km

R = input ( 'radius of the rotor in m is R= ')

T = 9.81 * R

C=1

K = T / C

N = input ('rated speed in rpm is N = ')

FO = T / N

 

RC = 174 % resistance ohm

V = input ('supply voltage,V= ')

% IR is current through reference winding, Amp

IR = input ('current through reference winding IR= ')

% IC is current through control winding, Amp

IC = input ('current through control winding IC= ')

No_load_input = V *(IR+IC)

Copper_loss_in_watts = IC^2 * RC

Constant_loss_in_watts = No_load_input - Copper_loss_in_watts

 

% Frictional loss W is 30 % of constant loss in Watts

W = Constant_loss_in_watts *30/100

 

% Frictional_co-efficient

F = W / (2 *N / 60)^2

 

Km = K / FO + F

 

d =39.5e-3            % diameter of the rotor in m

 

LR =76e-3             % length of the rotor in m

rho=7.8*10^(-1)       % density

J = pi*d*4* LR*rho / 32

tau_m=J / FO + F

 

% Gm (s) = Km / (1+ s m)

Gm = tf(Km, [tau_m 1])

bode(Gm)

grid

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Result- 

radius of the rotor in m is R= 0.15

R =

    0.1500

T =

    1.4715

C =

     1

K =

    1.4715

rated speed in rpm is N = 3000

N =

        3000

FO =

   4.9050e-04

RC =

   174

supply voltage,V= 220

V =

   220

current through reference winding IR= 4

IR =

     4

current through control winding IC= 3

IC =

     3

No_load_input =

        1540

Copper_loss_in_watts =

        1566

Constant_loss_in_watts =

   -26

W =

   -7.8000

F =

  -7.8000e-04

Km =

   3.0000e+03

d =

    0.0395

LR =

    0.0760

rho =

    0.7800

J =

   9.1953e-04

tau_m =

    1.8739

Gm =

 

     3000

  -----------

  1.874 s + 1

 

Continuous-time transfer function.

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Related Post – 

Simulate Speed and position control of DC Motor in MATLAB

Matlab- Design and develop a linear model for a DC motor

For more matlab code and program

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